Wizardに尋ねる #61
8デッキのバカラにて、プレイヤーとバンカーの両方が同じ取引下でエースと8のダイアモンドを獲得する確率はどれくらいですか？
(82/combin(416,2))* (72/combin(414,2)) = 0.00000043, or 1 in 2308093
バカラのプログレッシブ賭けシステムはありますか？また、このための特定のサイトはありますか？
たくさんありますが、どれも利用価値がありません。
First let me say I think your web site is absolutely outstanding. Thanks. I watched a new craps game being played at Grand Casino, Biloxi, MS. called "Four The Money". To win the shooter must throw the dice 4 times without a 7 coming up. What are the odds of throwing the dice:
4 times without throwing a 7?
3 times without throwing a 7?
2 times without throwing a 7?
1 times without throwing a 7?
How does the math work for this? Thanks
You’re welcome, thanks for the kind words. The probability of throwing the dice n times without a 7, and then throwing a 7, is (5/6)n*(1/6). The probability of throwing n non-sevens, without specifying the next throw would be (5/6)n. So the probability of throwing the dice at least four times without a seven would be (5/6)4=625/1296=0.4823.